Question

What is the the vertex of `y = -12x^2 - 2x - 6`?

Answer 1

`(-1/12, -71/12)`

Explanation:

Write the equation in vertex form as follows:

y= `-12(x^2 +x/6) -6`

= `-12(x^2 +x/6+ 1/144- 1/144)-6`

=`-12(x+1/12)^2 -6+12/144`

=`-12(x+1/12)^2 -71/12`

The vertex is therefore `(-1/12, -71/12)`