What is the the vertex of #y = 3x^2 - 12x - 24 #?
The vertex of the parabola is at (2,-36)
The equation of parabola is in the form of ax^2+bx+c; here a=3 , b=-12 and c=-24
We know the x-co-ordinate of the vertex is -b/2a ; So here the x-co-ordinate of vertex is 12/6 =2
Now putting x= 2 in the equation y=3x^2-12x-24 we get y= 32^2-122-24 or y=12-24-24; or y=-36
So the Vertex is at (2,-36)