# What is the the vertex of y = 5(x-1)^2+4?

Jan 3, 2016

This equation is already in vertex form ...

$y = a {\left(x - h\right)}^{2} + k$

where, vertex $= \left(h , k\right)$

#### Explanation:

So, for this problem ...

vertex $= \left(h , k\right) = \left(1 , 4\right)$

hope that helped