# What is the the vertex of y = x^2 +12x +14?

$\left(- 6 , - 22\right)$
$y = {\left(x + 6\right)}^{2} - 36 + 14$
$y = {\left(x + 6\right)}^{2} - 22$
There fore the vertex is the minimum value of the expression i.e. $\left(- 6 , - 22\right)$