# What is the the vertex of y = -x^2 - 12x - 4 ?

Aug 25, 2017

Vertex is at $\left(- 6 , 32\right)$

#### Explanation:

$y = - {x}^{2} - 12 x - 4 \mathmr{and} y = - \left({x}^{2} + 12 x\right) - 4$

$y = - \left({x}^{2} + 12 x + 36\right) + 36 - 4$

$y = - {\left(x + 6\right)}^{2} + 36 - 4 = - {\left(x + 6\right)}^{2} + 32$ . Comparing with

vertex form of equation y = a(x-h)^2+k ; (h,k) being vertex ,

we find here $h = - 6 , k = 32 \therefore$ Vertex is at $\left(- 6 , 32\right)$ [Ans]