# What is the the vertex of y = x^2-14x+13?

Mar 15, 2016

$\left(7 , - 36\right)$

#### Explanation:

$y = {x}^{2} - 14 x + 13 = {\left(x - 7\right)}^{2} - 49 + 13 = {\left(x - 7\right)}^{2} - 36$

Slightly rephrasing:

$y = 1 {\left(x - 7\right)}^{2} + \left(- 36\right)$

This is in standard vertex form:

$y = a \left(x - h\right) + k$

where $\left(h , k\right) = \left(7 , - 36\right)$ is the vertex and $a = 1$ the multiplier.

graph{x^2-14x+13 [-15, 29.38, -44.64, -22.44]}