# What is the the vertex of y = x^2 - 2x - 16?

Apr 3, 2017

minimum at $- 17$

#### Explanation:

$y = {x}^{2} - 2 x - 1 6$

by using completing a square,

$y = {\left(x - 1\right)}^{2} - {\left(- 1\right)}^{2} - 1 6$

$y = {\left(x - 1\right)}^{2} - 17$

vertex is minimum at $- 17$