# What is the the vertex of y =-x^2-3x-6 ?

Apr 10, 2018

$\left(- \frac{3}{2} , - \frac{3}{2}\right)$

#### Explanation:

$\frac{- b}{2 a}$ is the $x$ coordinate at this point

$\frac{- - 3}{2 \times - 1}$ =$\frac{3}{- 2}$

Put this value into the equation to find the $y$ value

${\left(- \frac{3}{- 2}\right)}^{2} - 3 \times \left(\frac{3}{- 2}\right) - 6$

= $\frac{9}{4} + \frac{9}{4} - 6$= $\frac{18}{4} - 6$

=$- \frac{3}{2}$