# What is the the vertex of y =-x^2 - 4x - 10?

May 27, 2016

The vertex is at the point (-2,-6)

#### Explanation:

The equation of the parabola is given by:

$y = a {\left(x - h\right)}^{2} + k$

The vertex of the parabola is at the point $\left(h , k\right)$

Rearrange the equation $y = - {x}^{2} - 4 x - 4 - 6$

$y = \left(- {x}^{2} - 4 x - 4\right) - 6$
$y = - \left({x}^{2} + 4 x + 4\right) - 6$
$y = - {\left(x + 2\right)}^{2} - 6$
$y = - {\left(x - \left(- 2\right)\right)}^{2} - 6$

$h = - 2 \text{ and } k = - 6$

Vertex is at $\left(- 2 , - 6\right)$

graph{-x^2-4x-10 [-6.78, 3.564, -9.42, -4.25]}