# What is the the vertex of y = (x + 3)^2 ?

##### 1 Answer
Jan 29, 2016

vertex: $\left(- 3 , 0\right)$

#### Explanation:

$y = {\left(x + 3\right)}^{2}$
could be written as
$\textcolor{w h i t e}{\text{XXX}} y = \textcolor{g r e e n}{1} {\left(x - \left(\textcolor{red}{- 3}\right)\right)}^{2} + \textcolor{b l u e}{0}$

Which is of the general "vertex form"
$\textcolor{w h i t e}{\text{XXX}} y = \textcolor{g r e e n}{k} {\left(x - \textcolor{red}{a}\right)}^{2} + \textcolor{b l u e}{b}$
with vertex at $\left(\textcolor{red}{a} , \textcolor{b l u e}{b}\right)$