# What is the the vertex of y = (x - 3)^2 + 5x-12 ?

Jun 22, 2016

$\left(\frac{1}{2} , - \frac{13}{4}\right)$

#### Explanation:

$y = {\left(x - 3\right)}^{2} + 5 x - 12$
$y = {x}^{2} - 6 x + 9 + 5 x - 12$
$y = {x}^{2} - x - 3$
$y = {x}^{2} - x + \frac{1}{4} - 3 - \frac{1}{4}$
$y = {\left(x - \frac{1}{2}\right)}^{2} - \frac{13}{4}$

Vertex $\left(\frac{1}{2} , - \frac{13}{4}\right)$