What is the the vertex of y = (x - 3)^2 + 5x-12 y=(x−3)2+5x−12? Algebra Quadratic Equations and Functions Quadratic Functions and Their Graphs 1 Answer 冠廷 李. Jun 22, 2016 (1/2,-13/4)(12,−134) Explanation: y=(x-3)^2+5x-12y=(x−3)2+5x−12 y=x^2-6x+9+5x-12y=x2−6x+9+5x−12 y=x^2-x-3y=x2−x−3 y=x^2-x+1/4-3-1/4y=x2−x+14−3−14 y=(x-1/2)^2-13/4y=(x−12)2−134 Vertex (1/2,-13/4)(12,−134) Answer link Related questions What are the important features of the graphs of quadratic functions? What do quadratic function graphs look like? How do you find the x intercepts of a quadratic function? How do you determine the vertex and direction when given a quadratic function? How do you determine the range of a quadratic function? What is the domain of quadratic functions? How do you find the maximum or minimum of quadratic functions? How do you graph y=x^2-2x+3y=x2−2x+3? How do you know if y=16-4x^2y=16−4x2 opens up or down? How do you find the x-coordinate of the vertex for the graph 4x^2+16x+12=04x2+16x+12=0? See all questions in Quadratic Functions and Their Graphs Impact of this question 1535 views around the world You can reuse this answer Creative Commons License