What is the the vertex of #y=(x - 8)^2 + 48 #?
1 Answer
Jan 22, 2017
Explanation:
The equation of a parabola in
#color(blue)"vertex form"# is.
#color(red)(bar(ul(|color(white)(2/2)color(black)(y=a(x-h)^2+k)color(white)(2/2)|)))#
where (h ,k) are the coordinates of the vertex and a, is a constant.
#"For " y=(x-8)^2+48#
#a=1,h=8" and " k=48#
#rArr"vertex "=(8,48)#
graph{(x-8)^2+48 [-160, 160, -80, 80]}