# What is the the vertex of y=(x - 8)^2 + 48 ?

Jan 22, 2017

$\left(8 , 48\right)$

#### Explanation:

The equation of a parabola in $\textcolor{b l u e}{\text{vertex form}}$ is.

$\textcolor{red}{\overline{\underline{| \textcolor{w h i t e}{\frac{2}{2}} \textcolor{b l a c k}{y = a {\left(x - h\right)}^{2} + k} \textcolor{w h i t e}{\frac{2}{2}} |}}}$
where (h ,k) are the coordinates of the vertex and a, is a constant.

$\text{For } y = {\left(x - 8\right)}^{2} + 48$

$a = 1 , h = 8 \text{ and } k = 48$

$\Rightarrow \text{vertex } = \left(8 , 48\right)$
graph{(x-8)^2+48 [-160, 160, -80, 80]}