What is the trigonometric form of # (3+6i) #?

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Hi Share
May 17, 2018

Answer:

#z= 3sqrt5(cos(63.43^@)+isin(63.43^@))#

Explanation:

Determine #r#
#r=sqrt(x^2+y^2)#

#r=sqrt(45)=3sqrt5#

To find #theta#
#theta= arctan(b/a)#
#theta= arctan(6/3)=63.43^@#

In trigonometric form:
#z= 3sqrt5(cos(63.43^@)+isin(63.43^@))#

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