# What is the value of 3+y-:4, when y=16?

Mar 26, 2018

The answer is $7.$

#### Explanation:

First, you plug the $y = 16$ into the problem, so it looks like this:
$3 + \frac{16}{4}$

$3 + \left(\frac{16}{4}\right)$
$3 + \left(4\right)$
$7$

Mar 26, 2018

See below.

#### Explanation:

When solving this expression, first we need to remember to follow the Order of Operations .

This operation is commonly referred to as $P E M D A S$. This is an acronym used by many in a way to remember these important steps:

$P$ - Parenthesis

$E$ - Exponents

$M D$ - Multiply/Divide (left to right)

$A S$ - Add/Subtract (left to right)

Now that we know this, we can being to simplify this expression. Luckily for us, it has given us the value of $y$, so all we have to do is to plug said value into the expression:

$3 + y \div i \mathrm{de} 4 \implies 3 + \left(16\right) \div i \mathrm{de} 4$

Now we simply solve using the above steps in order form top to bottom:

$3 + \left(16\right) \div i \mathrm{de} 4$

$= 3 + 4$

$= 7$

Mar 26, 2018

$7$

#### Explanation:

Be careful about the order of operations.

There are two terms. Calculate an answer for each first, which means doing the division of the second term first.

$\textcolor{b l u e}{3} \text{ "+" } \textcolor{red}{y \div 4}$

$= \textcolor{b l u e}{3} \text{ "+" } \textcolor{red}{16 \div 4}$

$= \textcolor{b l u e}{3} \text{ "+" } \textcolor{red}{4}$

$= 7$