What is the value of side c?

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Please help Im clueless and have been consulting the book for almost an hour now.

2 Answers
Feb 22, 2018

#c = 20#

Explanation:

#c# is #20# because

#sin(C)# is #5/6#

Sine is also known as

#"opposite"/"hypotenuse"#

#5# would be the opposite side from #"point C"#, and #6# would be the #"hypotenuse"#. It also tells us #b# is #24#.

In our ratio of #"side c"# to #"side b"#, we know it is #5/6#, so we can rewrite it as

#5/6 = x/24#

Multiplying #5/6# by #24# to isolate #x#, we get #(5*24)/6 = x#

#120/6# equals #x#, and finally we get #20 = x#, giving us #"side c"#, or the longer leg, as #20#.

Feb 22, 2018

#20# units

Explanation:

Let's start with the equation we have:

#sin(C)=5/6#

We can take the inverse #sin# (#arcsin#) to solve for angle C, which will help us solve for side c.

#arcsin(sin(C))= arcsin(5/6)# (#arcsin# cancels with #sin#)

#C~~0.985# radians (#56.44269024# degrees)

#C=56.44269024# degrees. Relative to angle C, side c is the opposite side, and side b is obviously the hypotenuse. We can use the mnemonic SOH-CAH-TOA:

SOH- Sine=opp/hyp
CAH- Cosine=adj/hyp
TOA- Tangent= opp/adj

Sine is the trig ratio that uses opposite and adjacent. Now, we can set up our equation:

#sin(56.44269024)=c/24#

We can multiply both sides by #24# to isolate c, and we get:

#c=24sin(56.44269024)#

#c=20# units