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What is the value of #y# in the equation #6.4x+2.8y = 44.4# , when #x=3#?

1 Answer
Jul 24, 2016

Answer:

#y=9#

Explanation:

#6.4x+2.8y=44.4#
Multiplying both the sides by #10#
we get
#64x+28y=444#
when #x=3# we get value of #y# as follows
#64(3)+28y=444#
or
#192+28y=444#
or
#28y=444-192#
or
#28y=252#
or
#y=252/28#
or
#y=9#