Question

What is the vertex and focus of the parabola described by `x^2-4x+y+3=0`?

Answer 1

`x^2-4x+y+3=0`
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`y=-x^2+4x-3`
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`y=-(x^2-4x+3)`
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`y=-(x^2-4x+3+1-1)`
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`y=-(x^2-4x+4-1)`
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`y=-(x^2-4x+4)+1`
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`y=-(x-2)^2+1`
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The vertex of the parabola is `(2,1)`
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The focus of thus parabola is `-1/4`