What is the vertex form of f(x) = -5x^2-2x+9 ? Algebra Quadratic Equations and Functions Vertex Form of a Quadratic Equation 1 Answer Binayaka C. Feb 12, 2018 Vertex is (-0.2 , 9.2) and vertex form of equation is f(x) = -5(x+0.2)^2+9.2 Explanation: f(x) = -5x^2-2x+9 or f(x) = -5(x^2+0.4x)+9 or f(x) = -5(x^2+0.4x+(0.2)^2)+5*0.04+9 or f(x) = -5(x+0.2)^2+9.2 . Vertex is (-0.2 , 9.2) and vertex form of equation is f(x) = -5(x+0.2)^2+9.2 [Ans] Answer link Related questions What is the Vertex Form of a Quadratic Equation? How do you find the vertex form of a quadratic equation? How do you graph quadratic equations written in vertex form? How do you write y+1=-2x^2-x in the vertex form? How do you write the quadratic equation given a=-2 and the vertex (-5, 0)? What is the quadratic equation containing (5, 2) and vertex (1, –2)? How do you find the vertex, x-intercept, y-intercept, and graph the equation y=-4x^2+20x-24? How do you write y=9x^2+3x-10 in vertex form? What is the vertex of y=-1/2(x-4)^2-7? What is the vertex form of y=x^2-6x+6? See all questions in Vertex Form of a Quadratic Equation Impact of this question 1817 views around the world You can reuse this answer Creative Commons License