# What is the vertex form of x = (y - 3)^2 + 41?

##### 1 Answer
Aug 3, 2017

$x = {\left(y - 3\right)}^{2} + 41$ is in the vertex form.

#### Explanation:

The vertex form for a parabola that opens to the left or right is:

$x = \frac{1}{4 f} {\left(y - k\right)}^{2} + h \text{ [1]}$

where $\left(h , k\right)$ is the vertex and $f = {y}_{\text{focus}} - k$.

The given equation

$x = {\left(y - 3\right)}^{2} + 41$

is already in the form of equation [1] where $\left(h , k\right) = \left(41 , 3\right) \mathmr{and} f = \frac{1}{4}$.