What is the vertex form of #y= 25x^2 + 5x #?

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Answer 1 · 2018-04-21T11:42:38

The vertex form of equation is #y=25 (x+0.1)^2 - 0.25#

#y= 25 x^2+5 x or y = 25 (x^2+0.2 x)# or

#y=25 (x^2+0.2 x +0.1^2) -25*0.01# or

#y=25 (x+0.1)^2 - 0.25# . Comparing with vertex form of

equation #f(x) = a(x-h)^2+k ; (h,k)# being vertex we find

here #h= -0.1 , k= -0.25 :.# Vertex is at #(-0.1,-0.25) #

The vertex form of equation is #y=25 (x+0.1)^2 - 0.25#

graph{25x^2+5x [-5, 5, -2.5, 2.5]}