Question

What is the vertex form of `y=2x^2 – 3x – 5`?

Answer 1

Vertex form of `y=2x^2-3x-5` is `y=2(x-3/4)^2-49/8`

Explanation:

`y=2x^2-3x-5=2(x^2-3/2x)-5=2(x^2-3/2x+9/16)-9/8-5=2(x-3/4)^2-49/8:.`Vertex is at `(3/4,-49/8)` graph{2x^2-3x-5 [-20, 20, -10, 10]}[Ans]