# What is the vertex form of y=2x^2 – 3x – 5 ?

Vertex form of $y = 2 {x}^{2} - 3 x - 5$ is $y = 2 {\left(x - \frac{3}{4}\right)}^{2} - \frac{49}{8}$
$y = 2 {x}^{2} - 3 x - 5 = 2 \left({x}^{2} - \frac{3}{2} x\right) - 5 = 2 \left({x}^{2} - \frac{3}{2} x + \frac{9}{16}\right) - \frac{9}{8} - 5 = 2 {\left(x - \frac{3}{4}\right)}^{2} - \frac{49}{8} \therefore$Vertex is at $\left(\frac{3}{4} , - \frac{49}{8}\right)$ graph{2x^2-3x-5 [-20, 20, -10, 10]}[Ans]