Question

What is the vertex form of `y= (2x-3)(3x-12)+4x^2+5x`?

Answer 1

In Vertex form `y=10*(x-7/5)^2+82/5`

Explanation:

`y=(2x-3)(3x-12)+4x^2+5x or y=6x^2-33x+36+4x^2+5x or y=10x^2-28x+36 or y = 10(x^2-14/5*x+(7/5)^2)-98/5+36 or y=10*(x-7/5)^2+82/5`. Vertex is at `(7/5,82/5)` graph{10(x-7/5)^2+82/5 [-160, 160, -80, 80]}[Ans]