# What is the vertex form of  y= (2x-3)(3x-12)+4x^2+5x?

In Vertex form $y = 10 \cdot {\left(x - \frac{7}{5}\right)}^{2} + \frac{82}{5}$
$y = \left(2 x - 3\right) \left(3 x - 12\right) + 4 {x}^{2} + 5 x \mathmr{and} y = 6 {x}^{2} - 33 x + 36 + 4 {x}^{2} + 5 x \mathmr{and} y = 10 {x}^{2} - 28 x + 36 \mathmr{and} y = 10 \left({x}^{2} - \frac{14}{5} \cdot x + {\left(\frac{7}{5}\right)}^{2}\right) - \frac{98}{5} + 36 \mathmr{and} y = 10 \cdot {\left(x - \frac{7}{5}\right)}^{2} + \frac{82}{5}$. Vertex is at $\left(\frac{7}{5} , \frac{82}{5}\right)$ graph{10(x-7/5)^2+82/5 [-160, 160, -80, 80]}[Ans]