What is the vertex form of y=3x^2+4x+1y=3x2+4x+1?

1 Answer
Jun 12, 2018

y = 3(x + 2/3)^2 + 7/3y=3(x+23)2+73

Explanation:

y = 3x^2 + 4x + 1y=3x2+4x+1
x-coordinate of vertex:
x = -b/(2a) = -4/6 = -2/3x=b2a=46=23
y-coordinate of vertex:
y(-2/3) = 12/9 - 8/3 +1 = 4/3 - 8/3 + 1= 7/3y(23)=12983+1=4383+1=73
Vertex (-2/3, 7/3)Vertex(23,73)
Vertex form of y:
y = 3(x + 2/3)^2 + 7/3y=3(x+23)2+73