Question

What is the vertex form of `y=3x^2+4x+1`?

Answer 1

`y = 3(x + 2/3)^2 + 7/3`

Explanation:

`y = 3x^2 + 4x + 1`
x-coordinate of vertex:
`x = -b/(2a) = -4/6 = -2/3`
y-coordinate of vertex:
`y(-2/3) = 12/9 - 8/3 +1 = 4/3 - 8/3 + 1= 7/3`
`Vertex (-2/3, 7/3)`
Vertex form of y:
`y = 3(x + 2/3)^2 + 7/3`