# What is the vertex form of y= x^2 + 4x + 4 ?

$y = {\left(x + 2\right)}^{2}$
The expression is already a square i.e. ${\left(x + 2\right)}^{2}$
Therefore the vertex form is $y = {\left(x + 2\right)}^{2}$
The vertex is $\left(- 2 , 0\right)$