What is the vertex form of y= x^2 – 7x – 4? Algebra Quadratic Equations and Functions Vertex Form of a Quadratic Equation 1 Answer salamat Jul 18, 2017 y = x^2 - 7 x - 4 use completing a square y = (x - 7/2)^2 - (-7/2)^2 - 4 y = (x - 7/2)^2 - 49/4 - 16/4 y = (x - 7/2)^2 - 65/4 since (x - 7/2)^2 is a +ve value, therefore it has a minimum vertex 7/2 at (7/2, -65/4) Answer link Related questions What is the Vertex Form of a Quadratic Equation? How do you find the vertex form of a quadratic equation? How do you graph quadratic equations written in vertex form? How do you write y+1=-2x^2-x in the vertex form? How do you write the quadratic equation given a=-2 and the vertex (-5, 0)? What is the quadratic equation containing (5, 2) and vertex (1, –2)? How do you find the vertex, x-intercept, y-intercept, and graph the equation y=-4x^2+20x-24? How do you write y=9x^2+3x-10 in vertex form? What is the vertex of y=-1/2(x-4)^2-7? What is the vertex form of y=x^2-6x+6? See all questions in Vertex Form of a Quadratic Equation Impact of this question 3816 views around the world You can reuse this answer Creative Commons License