# What is the vertex form of y=x^2 +x-6?

$y = {\left(x + \frac{1}{2}\right)}^{2} - \frac{25}{4}$
$y = {x}^{2} + x - 6$ => complete the square:
$y = {x}^{2} + x + {\left(\frac{1}{2}\right)}^{2} - 6 - \frac{1}{4}$ => simplify:
$y = {\left(x + \frac{1}{2}\right)}^{2} - \frac{25}{4}$ => in the vertex form