# What is the vertex form of y= (x +6)(x/3 + 2) ?

Apr 28, 2017

$y = \frac{1}{3} {\left(x + 6\right)}^{2}$

#### Explanation:

First you need to expan this function
$y = \frac{1}{3} {x}^{2} + 4 x + 12$
And then I need to make this function transform as this type
$y = a {\left(x - h\right)}^{2} + k$
So
$y = \frac{1}{3} \left({x}^{2} + 12 x + 36\right) + 12 - 12$
Final
$y = \frac{1}{3} {\left(x + 6\right)}^{2}$