Question

What is the vertex of the graph of `y=-1(x-2)^2`?

Answer 1

The vertex is at `(2,0)`

Explanation:

Consider the general vertex form for a parabola
`color(white)("XXX")y=color(green)(m)(x-color(red)(a))^2+color(blue)(b)`
for a parabola with vertex at `(color(red)(a),color(blue)(b))`

The given equation can be expressed in this form as
`color(white)("XXX")y=color(green)(-1)(x-color(red)(2))^2+color(blue)(0)`
a parabola with vertex at `(color(red)(2),color(blue)(0))`