What is the vertex of the graph of y = (x – 3)^2 + 4?

Jun 9, 2017

Vertex is $\left(3 , 4\right)$

Explanation:

In a vertex form of equation such as

$\left(y - k\right) = a {\left(x - h\right)}^{2}$

the vertex is $\left(h , k\right)$

As $y = {\left(x - 3\right)}^{2} + 4$

$\Leftrightarrow \left(y - 4\right) = 1 \times {\left(x - 3\right)}^{2}$

the vertex is $\left(3 , 4\right)$
graph{(x-3)^2+4 [-7.585, 12.415, -0.96, 9.04]}