Question

What is the vertex of the parabola? y+1=−14(x−2)2

Answer 1

`"vertex "=(2,-1)`

Explanation:

`"the equation of a parabola in "color(blue)"translated form"` is.

`•color(white)(x)(x-h)^2=4p(y-k)`

`"where "(h,k)" are the coordinates of the vertex"`

`"divide both sides by "-14`

`rArr(x-2)^2=-1/14(y+1)`

`"with "h=2" and "k=-1`

`rArrcolor(magenta)"vertex "=(2,-1)`
graph{y+1=-14(x-2)^2 [-10, 10, -5, 5]}