What is the vertex of the parabola #y=4x-x^2#?
1 Answer
Mar 17, 2016
Vertex is
Explanation:
Given -
#y=4x-x^2#
We shall rewrite it as -
#y=x^2+4x#
X- co-ordinate of the vertex is -
#x=(-b)/(2a)=-4/2=-2#
Y - co-ordinate at
#y=(-2)^2+4(-2)#
#y=4-8=-4#
Its vertex is -
#(-2, -4)#
