# What is the vertex of the parabola #y=4x-x^2#?

##### 1 Answer

Mar 17, 2016

Vertex is

#### Explanation:

Given -

#y=4x-x^2#

We shall rewrite it as -

#y=x^2+4x#

X- co-ordinate of the vertex is -

#x=(-b)/(2a)=-4/2=-2#

Y - co-ordinate at

#y=(-2)^2+4(-2)#

#y=4-8=-4#

Its vertex is -

#(-2, -4)#