What is the vertex of the parabola #y=(x-8)^2#?

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Answer 1 · 2016-05-30T07:28:16

Vertex is at point (8,0).

The parabola equation is of the form

#y=a(x-h)+k#

The vertex is at point # (h,k)#

The given equation is

#y=(x-8)^2#

So the vertex is at #(8,0)#

graph{(x-8)^2 [-0.39, 17.02, -2.586, 6.114]}