Question

What is the vertex of `y = 1/2 (3x + 2)^2 - 1/3`?

Answer 1

Vertex is at `(-2/3,-1/3)`

Explanation:

`y=1/2(3x+2)^2-1/3= 9/2(x+2/3)^2-1/3`Comparing with the vertex form of equation `y=a(x-h)^2+k` we get vertex is at `(-2/3,-1/3)` graph{1/2(3x+2)^2-1/3 [-5, 5, -2.5, 2.5]}[Ans]