What is the vertex of  y = 1/2 (3x + 2)^2 - 1/3 ?

Vertex is at $\left(- \frac{2}{3} , - \frac{1}{3}\right)$
$y = \frac{1}{2} {\left(3 x + 2\right)}^{2} - \frac{1}{3} = \frac{9}{2} {\left(x + \frac{2}{3}\right)}^{2} - \frac{1}{3}$Comparing with the vertex form of equation $y = a {\left(x - h\right)}^{2} + k$ we get vertex is at $\left(- \frac{2}{3} , - \frac{1}{3}\right)$ graph{1/2(3x+2)^2-1/3 [-5, 5, -2.5, 2.5]}[Ans]