# What is the vertex of # y = -1/2(4x - 3)^2 + 1/2 #?

##### 1 Answer

Jun 23, 2016

#### Explanation:

Note that for any Real value of

#(4x-3)^2 >= 0#

and is only equal to zero when:

#4x-3 = 0#

That is when

So this is the

Substituting this value of

So the vertex of the parabola is

graph{(y-(-1/2(4x-3)^2+1/2))((x-3/4)^2+(y-1/2)^2-0.001) = 0 [-2.063, 2.937, -1.07, 1.43]}