Question

What is the vertex of # y= -12x^2-4x-2?

Answer 1

The vertex is at `( -1/6 , -5/3)`

Explanation:

`y=-12 x^2-4 x-2`. Comparing with standard equation `ax^2+bx+c` we get `a= -12 , b= -4 ,c= -2`
`x` co-ordinate of vertex is `-b/(2 a) = -4/(2* -12) = -1/6`

Then, `y` co-ordinate of vertex is `y = -12(-1/6)^2-4(-1/6)-2= -5/3`
The vertex is at `( -1/6 , -5/3)` graph{-12x^2-4x-2 [-20, 20, -10, 10]}