What is the vertex of #y=2(x - 2)^2 -6 #? Algebra Quadratic Equations and Functions Quadratic Functions and Their Graphs 1 Answer Binayaka C. Apr 4, 2016 Vertex is at #(2,-6)# Explanation: The Vertax is at # (2,-6)# [Comparing with general form #y=a*(x-h)^2+k# where (h,k) is the Vertex]. graph{2(x-2)^2-6 [-20, 20, -10, 10]}[Ans] Answer link Related questions What are the important features of the graphs of quadratic functions? What do quadratic function graphs look like? How do you find the x intercepts of a quadratic function? How do you determine the vertex and direction when given a quadratic function? How do you determine the range of a quadratic function? What is the domain of quadratic functions? How do you find the maximum or minimum of quadratic functions? How do you graph #y=x^2-2x+3#? How do you know if #y=16-4x^2# opens up or down? How do you find the x-coordinate of the vertex for the graph #4x^2+16x+12=0#? See all questions in Quadratic Functions and Their Graphs Impact of this question 2638 views around the world You can reuse this answer Creative Commons License