What is the vertex of y=-2x^2 + 2x + 5 ?
2 Answers
Aug 10, 2017
Explanation:
"given the equation of a parabola in standard form"
"that is "y=ax^2+bx+c
"then "x_(color(red)"vertex")=-b/(2a)
y=-2x^2+2x+5" is in standard form"
"with "a=-2,b=+2,c=5
rArrx_(color(red)"vertex")=-2/(-4)=1/2
"substitute this value into the equation for the corresponding"
"y-coordinate"
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rArrcolor(magenta)"vertex "=(1/2,11/2)
Aug 10, 2017
Vertex is at
Explanation:
The axis of symmetry is also the x value of the vertex. So we can use the formula
Substitute
Therefore, the vertex is at