Question

What is the vertex of `y= 2x^2+5x-13-4(x-1)^2`?

Answer 1

The vertex is `(13/4 , 33/8)`.

Explanation:

We expand and combine like terms:
`y = 2x^2-4x^2+5x+8x-13-4 = -2x^2+13x-17`
The x-coordinate of the vertex is:
`x = -\frac{b}{2a} = 13/4 = 3 1/4`
`y = 33/8 = 4 1/8`
Therefore, the vertex is `(13/4 , 33/8)`.