What is the vertex of #y= 2x^2 +5x + 30#?
2 Answers
The vertex of
Explanation:
For a parabola in standard form:
the vertex is the point where
NB: This point will be a maximum or minimum of
In our example:
Replacing for
The vertex of
We can see this point as the minimum of
graph{2x^2+5x+30 [-43.26, 73.74, -9.2, 49.34]}
To find the vertex, the easiest thing to do (besides graphing the problem) is to convert the equation into vertex form. To do that, we should "complete the square"
the leading coefficient must be
We need to find a value that changes
To do that, we need to take the middle term,
Our next step is to square the result:
Now we have our missing value:
So, our problem really is
Let's rewrite this:
Now let's look at our equation again:
Let's combine like-terms:
Now we have the equation in vertex form, and we can find the vertex very easily from here
That's the vertex.
To check our work, let's graph our equation and see the vertex
graph{y=2x^2+5x+30}
We were right!