What is the vertex of y=3(3x-3)^2+3?

Nov 24, 2015

vertex: $\left(1 , 3\right)$

Explanation:

$\textcolor{w h i t e}{\text{XXX}} y = m {\left(x - a\right)}^{2} + b$
is in "vertex form" with a vertex at $\left(a , b\right)$
$y = 3 {\left(3 x - 3\right)}^{2} + 3 = 3 \left({3}^{2} {\left(x - 1\right)}^{2}\right) + 3 = 27 {\left(x - 1\right)}^{2} + 3$
which is in "vertex form" with vertex at $\left(1 , 3\right)$