What is the vertex of #y= -3x^2+5#?
1 Answer
Dec 14, 2015
Vertex is
Explanation:
Given -
#y=-3x^2+5#
You shall have it as -
#y=-3x^2+0x+5#
Now it is in the form of#y = ax^2+bx+c#
#x=(-b)/(2 xx a)= (-0)/(2 xx -3)=0#
At
Vertex is