# What is the vertex of y= -3x^2+5?

Dec 14, 2015

Vertex is $\left(0 , 5\right)$

#### Explanation:

Given -

$y = - 3 {x}^{2} + 5$
You shall have it as -
$y = - 3 {x}^{2} + 0 x + 5$
Now it is in the form of $y = a {x}^{2} + b x + c$

$x = \frac{- b}{2 \times a} = \frac{- 0}{2 \times - 3} = 0$

At x=0 ; y=-3(0)^2+5=5

Vertex is $\left(0 , 5\right)$