# What is the vertex of # y=-3x^2+5x+6#?

##### 3 Answers

#### Explanation:

The vertex can be found using differentiation, differentiating the equation and solving for 0 can determine where the x point of the vertex lies.

Thus the

Now we can substitute

#### Explanation:

#"for a parabola in standard form " y=ax^2+bx+c#

#"the x-coordinate of the vertex is " x_(color(red)"vertex")=-b/(2a)#

#y=-3x^2+5x+6" is in standard form"#

#"with " a=-3,b=5,c=6#

#rArrx_(color(red)"vertex")=-5/(-6)=5/6#

#"substitute this value into the function for y-coordinate"#

#rArry_(color(red)"vertex")=-3(5/6)^2+5(5/6)+6=97/12#

#rArrcolor(magenta)"vertex "=(5/6,97/12)#

#### Explanation:

*[Standard Form of a Quadratic Equation]*

**TO FIND THE X-VALUE OF THE VERTEX:**

Use the formula for the axis of symmetry by substituting values for

**TO FIND THE Y-VALUE OF THE VERTEX:**

Use the formula below by substituting values for

**Express as a coordinate.**