Question

What is the vertex of y=3x^2+6?

Answer 1

`(0,6)`

Explanation:

This is a 2nd degree quadratic function so its graph will be a parabola.
Such function of form `y=ax^2+bx+c` has turning point at `x=-b/(2a)`, so in this case at `x=0` which implies corresponding y-value is at the y-intercept itself of `6`.

Here is the graph as verification :

graph{3x^2+6 [-24.28, 40.64, -4.72, 27.74]}