What is the vertex of # y= 5x^2-2x-1+(2x-1)^2#?

Question

1364 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-02-05T07:11:55

#V(1. -3)#. See Socratic graph.

y=9x^2-6x, and in the standard form, this is

#(x-1)^2=1/3(y+3)#, revealing

vertex at V(1, -3),

axis along #x = 1 uarr#.

size #a =1/12# and

focus at #S(1, -35/12)#

graph{(3x^2- 6x-y)((x-1)^2+(y+3)^2-.01)=0x^2 [-10, 10, -5, 5]}