What is the vertex of y=9(5x-2)^2+3?

The vertex form is written as $y = a {\left(x - h\right)}^{2} + k$, where the a value determines the direction of opening (if a > 0, then it opens upwards and if a < 0, then it opens downward); h represents the x-coordinate of the vertex; k represents the y-coordinate of the vertex; x and y represent the x- and y-coordinates of a point on the parabola, other than the vertex.
$y = 9 \cdot {\left(5 \left(x - \frac{2}{5}\right)\right)}^{2} + 3 \implies y = 9 \cdot {5}^{2} \cdot {\left(x - \frac{2}{5}\right)}^{2} + 3$