# What is the vertex of y= -(x+1)^2 +17 ?

Dec 16, 2015

vertex$= \left(- 1 , 17\right)$

#### Explanation:

The general equation of a quadratic equation in vertex form is:

$y = a {\left(x - h\right)}^{2} + k$

where:
$a =$vertical stretch/compression
$h =$x-coordinate of vertex
$k =$y-coordinate of vertex

Looking back at the equation, $y = - {\left(x + 1\right)}^{2} + 17$, we can see that:

• $h = - 1$
• $k = 17$

Keep in mind that $h$ is negative and not positive even though it appears to be in the equation.

$\therefore$, the vertex is $\left(- 1 , 17\right)$.

Dec 16, 2015

Vertex (-1, 17)

#### Explanation:

y is expressed in vertex form.
Vertex (-1, 17)